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April 16, 2014

April 16, 2014

Posted by **m** on Tuesday, March 5, 2013 at 8:57pm.

Define the half life. The half-life of a radioisotope is found to be 4.55 minutes. If the decay follows first order kinetics, what percentage of isotope will remain after 2.00 hours if you start with 10.00 g?

T1/2= (.693)/k 4.55min = (.693)/k k =.152min-1

- Chemistry -
**m**, Tuesday, March 5, 2013 at 10:31pmNever mind I figured it out

Ln(At)=-(.152min-1)(120min)+ln(10)

Ln(At)= -18.24+(2.30)

Ln(At)=-15.9

e^At=e^-15.9

At= 1.19 x 10^-7

%=1.19 x 10^-7 x 100

=1.19 x 10^-5 % of the isotope

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