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November 24, 2014

November 24, 2014

Posted by **Michael** on Tuesday, March 5, 2013 at 7:52pm.

- physics -
**drwls**, Tuesday, March 5, 2013 at 8:07pmThe grabbing of Jane at the lowest point of the swing is a momentum-conserving event, but some kinetic energy is lost. Then they swing to the highest point with energy conserved again.

Let Tarzan's speed before grabbing Jane = V1:

Tarzan's mass = Mt

Jane's mass = Mj

Mt*g*(1-cos25.9) = (Mt/2)*V1^2

V1 = sqrt[2*g*(1-cos25.9)] = 1.403 m/s

After grabbing Jane,

V1*Mt = V2(Mt+Mj)

V2 = V1*[Mt/(Mt+Mj)]= 0.641V1 = 0.899 m/s

Final maximum angle A is given by

g(1-cosA) = (1/2)V2^2

1 - cosA = 0.04126

cosA = 0.9587

A = 16.5 degrees

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