Posted by **Chuck** on Tuesday, March 5, 2013 at 3:17pm.

Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 236 miles in the same time that Dana travels 224 miles. If Chuck’s rate of travel is 3 mph more than Dana’s, and they travel the same length of time, at what speed does Chuck travel?

- Algebra -
**Henry**, Wednesday, March 6, 2013 at 8:42pm
r mi/h = Dana's rate.

r * t = 224 miles.

t = 224/r.

3)224r+3) mi/h = Chuck's rate.

(r+3)t = 236

Replace t with 224/r:

(r+3)224/r = 236

Multiply both sides by r:

(r+3)224 = 236r

224r + 672 = 236r

236r - 224r = 672

12r = 672

r = 56 mi/h = Dana's speed.

r+3 = 59 mi/h = Chuck's speed.

- Algebra -
**Henry**, Wednesday, March 6, 2013 at 8:47pm
Correction: Chuck's rate = (r+3)mi/h.

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