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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Tuesday, March 5, 2013 at 12:32am.

- logic -
**Lauren**, Tuesday, March 5, 2013 at 12:35am3?

- logic -
**Dr. Jane**, Tuesday, March 5, 2013 at 12:13pmLet x = # of poles

2x + 1 = 3(x_1)

2 pigeons per pole with 1 pigeon

3 pigeons per poles with 1 less pole.

2x + 1 = 3x -3

x = 4 poles

You have 2 pigeons per pool = 8 pigeons + one left over = 9 pigeons.

3 pigeons per pole = 9 pigeons.

It looks like we have nine pigeons.

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