You drop a rock off a bridge. The rock's height, h(in feet above the water), after t seconds is modeled by h=-16t2+541. What is the height of the rock after 2 seconds?
sub in t = 2
h =-16(4) + 541 = 477
12-42/3=
To find the height of the rock after 2 seconds, we need to substitute the value of t = 2 into the equation h = -16t^2 + 541.
Let's calculate it step by step:
First, substitute t = 2 into the equation:
h = -16(2)^2 + 541
Simplify the expression within the parentheses:
h = -16(4) + 541
Multiply:
h = -64 + 541
Add:
h = 477
Therefore, the height of the rock after 2 seconds is 477 feet.