A bird stands on a bare power line carrying 2500 amps of current. 600 meters of this wire has a resistance of .009 ohms. If the bird's feet are 3 cm apart, what is the voltage difference between the bird's feet?
To find the voltage difference between the bird's feet, we need to use Ohm's Law, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R):
V = I * R
First, we need to convert the resistance from ohms (Ω) to kiloohms (kΩ) since the given resistance is in ohms:
Resistance (R) = 0.009 Ω = 0.009 * 10^-3 kΩ = 9 * 10^-6 kΩ
Now, let's calculate the voltage difference by substituting the values into the formula:
V = 2500 A * (600 meters * 9 * 10^-6 kΩ)
First, let's simplify the equation inside the parentheses:
600 meters * 9 * 10^-6 kΩ = 5400 * 10^-6 kΩ = 5.4 * 10^-3 kΩ
Now, substitute the simplified value into the formula:
V = 2500 A * (5.4 * 10^-3 kΩ)
Now, we multiply the current and resistance to find the voltage:
V ≈ 13.5 volts
Therefore, the voltage difference between the bird's feet is approximately 13.5 volts.