Posted by **Raul** on Monday, March 4, 2013 at 6:59pm.

The position of a particle moving on a horizontal line is given by s(t)=2t^3-15t^2+24t-5, where s is measured in feet and t in seconds.

a: What is the initial position of the particle?

b: What is the average velocity of the particle on the interval [0,2]?Indicate units of measure

c: Find a formula for the instantaneous velocity of the particle.

d: When is the particle at rest?

e: When is the particle moving to the right? When is it moving to the left?

f: At t=2 seconds, is the particle moving away from the origin or towards the origin?

h: What is the average acceleration of the particle on the interval [0,2]?

i: Find a formula for the instantaneous acceleration of the particle.

j: At t=2 seconds, is the particle slowing down or speeding up?

- Calculus -
**Reiny**, Monday, March 4, 2013 at 9:09pm
a) sub in t = 0

b) avg vel = (s(2) - s(0) )/(2-0) = ...

c) s ' (t) = 6t^2 - 30t + 24

d) particle is at rest, when velocity = 0 , that is ...

6t^2 - 30t + 24 = 0

t^2 - 5t +4 = 0

(t-1)(t-4) = 0

when t = 1 or when t = 4

f) sub t=2 into the derivative of c)

if it is positive, ---> to the right

if it is negative, ---> to the left

e) same steps as b) except use the velocity expression

you do some of them.

- Calculus -
**Madds**, Monday, March 4, 2013 at 10:30pm
How do you do E on this problem??

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