Calculus
posted by Jade on .
Determine convergence of divergence. If convergent, find the sum.
Sum (infinity, n = 0) (e/pi)^n

1 + .865 + .865^2 +.865^3 ......
this is a geometric series with the first term one and every successive term multiplied by r =.865 (approx)
If r <1
then the geometric series converges.
for the series
a + a r + a r^2 + a r^3  a r^oo
the sum is
S = a/(1r)
here a = 1
and r = .865
S = 1/(1.865) = 7.4 