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March 30, 2015

March 30, 2015

Posted by **Jade** on Monday, March 4, 2013 at 3:47pm.

Sum (infinity, n = 0) (e/pi)^n

- Calculus -
**Damon**, Monday, March 4, 2013 at 4:14pm1 + .865 + .865^2 +.865^3 ......

this is a geometric series with the first term one and every successive term multiplied by r =.865 (approx)

If r <1

then the geometric series converges.

for the series

a + a r + a r^2 + a r^3 ----- a r^oo

the sum is

S = a/(1-r)

here a = 1

and r = .865

S = 1/(1-.865) = 7.4

- Calculus -
**Damon**, Monday, March 4, 2013 at 4:15pm

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