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Calculus

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Determine convergence of divergence. If convergent, find the sum.

Sum (infinity, n = 0) (e/pi)^n

  • Calculus -

    1 + .865 + .865^2 +.865^3 ......
    this is a geometric series with the first term one and every successive term multiplied by r =.865 (approx)
    If r <1
    then the geometric series converges.
    for the series
    a + a r + a r^2 + a r^3 ----- a r^oo
    the sum is
    S = a/(1-r)
    here a = 1
    and r = .865
    S = 1/(1-.865) = 7.4

  • Calculus -

    Read:
    http://en.wikipedia.org/wiki/Geometric_series

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