A mountain has an elevation or 19,389 feetin 1918, the glacier at the peak covered 4 acres, by 2003 this glacier had melted to 1 acre. What was the yearly rate of change. What is the equation that gives the acreage t years after 1918

The yearly rate of change

total amount of change divided by the number of years between 2003 and 1918.

acreage = the yearly rate(that you calculated) times t.

To find the yearly rate of change of the glacier's area, we need to calculate the difference in acreage divided by the difference in years.

First, let's find the difference in acreage: 4 acres - 1 acre = 3 acres.

Next, let's find the difference in years: 2003 - 1918 = 85 years.

Now we can calculate the yearly rate of change: 3 acres / 85 years ≈ 0.035 acres per year.

So, the yearly rate of change of the glacier's area is approximately 0.035 acres per year.

To find the equation that gives the acreage t years after 1918, we can use the concept of linear interpolation.

Given that in 1918 the acreage was 4 acres, and by 2003 it reduced to 1 acre, we can calculate the slope of the line connecting these two points.

Slope (m) = (change in y-coordinate) / (change in x-coordinate) = (1 acre - 4 acres) / (2003 - 1918 years) = -3 acres / 85 years ≈ -0.035 acres per year.

Using the point-slope form of a linear equation (y - y₁ = m(x - x₁)), we can write the equation for the acreage t years after 1918 as:

Acreage = 4 acres + (-0.035 acres/year) * (t - 1918 years).

In this equation, t represents the number of years after 1918, and Acreage represents the glacier's acreage at that specific time.