Post a New Question


posted by on .

Find the value of a so that the function f(x) = xe^(ax) has critical point at x = 9

I found that the derivative is axe^(ax)+e^(ax)

But I am not sure where to go from here?

  • Shayna - ,

    e^(ax) (ax+1) = 0 for derivative = 0
    a = -1/x
    a = -1/9

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question