Monday

March 30, 2015

March 30, 2015

Posted by **Calculus** on Monday, March 4, 2013 at 11:21am.

I found that the derivative is axe^(ax)+e^(ax)

But I am not sure where to go from here?

- Shayna -
**Damon**, Monday, March 4, 2013 at 11:32ame^(ax) (ax+1) = 0 for derivative = 0

so

a = -1/x

a = -1/9

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