Posted by **zachary** on Monday, March 4, 2013 at 11:01am.

given the following polynomial find the zero and multiply of each

were the graph touches the x axis

number of turning points

fx =(x-4)(x^2-25)

- college algebra -
**Dr. Jane**, Monday, March 4, 2013 at 12:08pm
0 = (x-4)(x+5)(x-5)

Set each equal to zero and solve for x. That will give you three different zeros. Each occurs only once.

- college algebra -
**Steve**, Monday, March 4, 2013 at 12:09pm
f(x) = (x-4)(x-5)(x+5)

3 roots, each of multiplicity 1

The graph crosses the axis at each root, so it has to turn around 2 times.

- college algebra -
**Anonymous**, Monday, March 4, 2013 at 3:47pm
4

-5

5

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