Posted by **Drew** on Sunday, March 3, 2013 at 11:32pm.

Althea invested $10,000 for one year, part at 7% and part at 6 1/4%. If she earned a total interest of

$656.50, how much was invested at each rate?

- Math -
**Dr. Jane**, Monday, March 4, 2013 at 9:30am
x = amount at 7%

y = amount at 6.25%

x + y = 10,000 or x = 10,000 - y

.07x + .0625y = 656.50

You can solve by substitution:

.07(10,000 - y) +.0625y = 656.50

## Answer this Question

## Related Questions

- algebra - two investments were made totaling $15,000. for a certain year these ...
- Math - An investment advisor invested a total of $12,000, part at 2.5% annual ...
- Math - Joe invested $12,000, part at 6% interest and part at 8% interest. In the...
- Math - A total of $11,000 was invested. Part of the $11,000 was invested at 4% ...
- algebra - Janet invested $23,000, part at 6% and part at 17%. If the total ...
- math - you invested $4000 in two accounts paying 2% and 9% annual interest, ...
- Algebra - Joe invested $12000, part at 6% interest and part at 8% interest. In ...
- Math Help Please - Bob invested $30,000, part at 10% and part at 1%. If the ...
- Math - John invested $2500, part at 8% and the rest at 12% per annum. The two ...
- math - if $9,000 is to be invested, part at 13% and the rest at 8% simple ...

More Related Questions