Friday

January 30, 2015

January 30, 2015

Posted by **Drew** on Sunday, March 3, 2013 at 11:32pm.

$656.50, how much was invested at each rate?

- Math -
**Dr. Jane**, Monday, March 4, 2013 at 9:30amx = amount at 7%

y = amount at 6.25%

x + y = 10,000 or x = 10,000 - y

.07x + .0625y = 656.50

You can solve by substitution:

.07(10,000 - y) +.0625y = 656.50

**Answer this Question**

**Related Questions**

algebra - two investments were made totaling $15,000. for a certain year these ...

Math - An investment advisor invested a total of $12,000, part at 2.5% annual ...

Math - Joe invested $12,000, part at 6% interest and part at 8% interest. In the...

Math - A total of $11,000 was invested. Part of the $11,000 was invested at 4% ...

algebra - Janet invested $23,000, part at 6% and part at 17%. If the total ...

math - you invested $4000 in two accounts paying 2% and 9% annual interest, ...

Algebra - Joe invested $12000, part at 6% interest and part at 8% interest. In ...

Math Help Please - Bob invested $30,000, part at 10% and part at 1%. If the ...

Math - John invested $2500, part at 8% and the rest at 12% per annum. The two ...

math - if $9,000 is to be invested, part at 13% and the rest at 8% simple ...