Posted by Drew on Sunday, March 3, 2013 at 11:32pm.
Althea invested $10,000 for one year, part at 7% and part at 6 1/4%. If she earned a total interest of
$656.50, how much was invested at each rate?

Math  Dr. Jane, Monday, March 4, 2013 at 9:30am
x = amount at 7%
y = amount at 6.25%
x + y = 10,000 or x = 10,000  y
.07x + .0625y = 656.50
You can solve by substitution:
.07(10,000  y) +.0625y = 656.50
Answer This Question
Related Questions
 algebra  two investments were made totaling $15,000. for a certain year these ...
 Math  An investment advisor invested a total of $12,000, part at 2.5% annual ...
 Math  Joe invested $12,000, part at 6% interest and part at 8% interest. In the...
 Algebra  The Smiths invested $14,000, part at 3% simple interest and the rest ...
 algebra  Janet invested $23,000, part at 6% and part at 17%. If the total ...
 Math  A total of $11,000 was invested. Part of the $11,000 was invested at 4% ...
 Algebra  Joe invested $12000, part at 6% interest and part at 8% interest. In ...
 math  you invested $4000 in two accounts paying 2% and 9% annual interest, ...
 Math Help Please  Bob invested $30,000, part at 10% and part at 1%. If the ...
 Math  John invested $2500, part at 8% and the rest at 12% per annum. The two ...
More Related Questions