three fair coins are tossed. What is the probability that at least one is tail. Enter probability as a fraction
HEAD IS 1/2 1/2 THATS #3.
#8 IS 2-6.#9 IS 1-4.#13 IS 4-4=1
To find the probability that at least one coin is a tail when three fair coins are tossed, we can use the concept of complementary probability.
The complementary probability of an event A is equal to 1 minus the probability of the event not occurring (A'). In this case, event A represents the event of having at least one tail when three fair coins are tossed.
The opposite event, event A', represents the event of having no tails when three coins are tossed. To find the probability of event A', we need to find the number of outcomes where all three coins show heads and divide it by the total number of possible outcomes when tossing three coins.
The total number of possible outcomes when tossing three coins is 2 * 2 * 2 = 8, as each coin has two possible outcomes (heads or tails), and the coins are tossed independently.
The number of outcomes where all three coins show heads is 1, as there is only one way for all three coins to show heads.
Therefore, the probability of event A' (no tails) is 1/8.
Now, we can find the probability of event A (at least one tail) by subtracting the probability of event A' from 1.
Probability of event A = 1 - Probability of event A'
= 1 - 1/8
= 7/8
So, the probability that at least one coin is a tail when three fair coins are tossed is 7/8.