Let 2^a = 5 and 2^b = 10. Using exponent rules, solve the equation in terms of a and b.
10^x =(1/64)
1/64 = 1/2^6
so
10^x = 2^-6
(2^b)^x = 2^-6
2^bx = 2^-6
so
b x = -6
but 2^b = 2*5 = 2*2^a = 2^(a+1)
so
b = a+1
(a+1)x = -6
10^x =(1/64)
so
10^x = 2^-6
(2^b)^x = 2^-6
2^bx = 2^-6
so
b x = -6
but 2^b = 2*5 = 2*2^a = 2^(a+1)
so
b = a+1
(a+1)x = -6