Posted by Enis on Sunday, March 3, 2013 at 5:48pm.
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Math elements
I think you are missing part of your question for B.
A can be a subset of itself, so it would include everything
The null or empty set is also a subset.
Each number could be in its own subset.
We are up to 8 subsets.
Also, we could take two numbers at a time to make unique subsets you would use combinations to do that. 6!/(2!4!)
Then you could take three numbers at a time: 6!/(3!3!)
Then you could take four numbers at a time: 6!/(4! 2!)
Finally, you could take five numbers at a time: 6!(5!1!)
Sum all of these and you will get the total number of subsets for A.
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