posted by Leanna on .
A 20 kg crate is placed on a horizontal conveyor belt. The materials are such that us = 0.47 and uk = 0.21.
What is the maximum acceleration the belt can have without the crate slipping?
If acceleration of the belt exceeds the value determined in part A, what is the acceleration of the crate?
Normal force = 20 * 9.81 = 196 N
.47 * 196 = 92.2 = max force without slipping
20 a = 92.2
a = 4.61 m/s^2 max without slip (we could have just said .47 g)
196 (.21) = 20 a
a = 2.06 m/s^2 while slipping