Homework Help: Physics

Posted by Tim on Sunday, March 3, 2013 at 2:50pm.

In a room that is 2.69 m high, a spring (unstrained length = 0.28 m) hangs from the ceiling. A board whose length is 2.22 m is attached to the free end of the spring. The board hangs straight down, so that its 2.22-m length is perpendicular to the floor. The weight of the board (145 N) stretches the spring so that the lower end of the board just extends to, but does not touch, the floor. What is the spring constant of the spring?

Physics - Elena, Sunday, March 3, 2013 at 3:24pm
Elongation of the spring is
x=2.69 –(2.22+0.28) = 0.19 m
mg= kx
k=mg/x- 145/0.19=763.16 N/m

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