Homework Help: Physics

Posted by Tim on Sunday, March 3, 2013 at 2:22pm.

A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1390 Hz. The bird-watcher, however, hears a frequency of 1430 Hz. What is the speed of the bird, expressed as a percentage of the speed of sound?

Physics - Elena, Sunday, March 3, 2013 at 3:18pm
f =f₀/(1-v/u)
f₀=1390 Hz
f=1430 Hz
v/u=(f-f₀)/f= (1430-1390) /1430=2.8•10⁻² m/s
v/u = 2.8%

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