math
posted by Moses on .
A flagpole and a building stands on the same horizontal level.From the point P at the bottom of the building.the angle of elevation of the top T of the flagpole is 65 degrees from the top Q of the building the angle of elevation of the point T is 25 degrees.If the building is 20m high,Calculate
(a)Distance PT
(b)Height of the flagpole
(c)Distance QT.

Draw a horizontal line from Q to the flagpole. Label the intersection S.
The height of the pole is thus 20+ST
since
SQ/ST = cot25
SQ/(ST+20) = cot65
equate and solve for ST
Now you can get SQ
PT^2 = SQ^2 + (ST+20)^2
QT^2 = SQ^2 + ST^2