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What volume (mL) of a 3.23 %w/v saline solution contains 69.1 mg of NaCl?

  • chemistry - ,

    (0.0691 g of NaCl/ x mL)*100=3.23% w.v saline solution

    Solve for x

    0.0691 g of NaCl/0.0323= volume in mL

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