A race car travels northward on a straight, level track at a constant speed travels 0.745 km in 22.0 s. The return trip over the same track is made in 27.0 s.

(a) What is the average velocity of the car in m/s for the first leg of the run?
m/s

(b) What is the average velocity for the total trip?
m/s

Distance = velocity x time

.745 = velocity x 22

divide both sides by 22 to get the velocity for the first leg.

.745 = velocity x 27

do the same to get the velocity for the second leg.

to get the average: add the two velocities and divide by two.

To find the average velocity, we need to divide the total distance traveled by the total time taken.

(a) To find the average velocity of the car in m/s for the first leg of the run, we need to convert the distance to meters and divide it by the time in seconds.

Given:
Distance = 0.745 km = 0.745 * 1000 m = 745 m
Time = 22.0 s

Average velocity = Distance / Time
Average velocity = 745 m / 22.0 s = 33.8636 m/s

Therefore, the average velocity for the first leg of the run is 33.8636 m/s.

(b) To find the average velocity for the total trip, we need to consider the total distance covered in the return trip as well. Since the car traveled in opposite direction during the return trip, the total distance covered will be the sum of the distances covered in the first and return trips.

Given:
Distance for first leg = 745 m
Time for first leg = 22.0 s
Time for return trip = 27.0 s

Total distance = Distance for first leg + Distance for return trip
Total distance = 745 m + 745 m = 1490 m

Total time = Time for first leg + Time for return trip
Total time = 22.0 s + 27.0 s = 49.0 s

Average velocity = Total distance / Total time
Average velocity = 1490 m / 49.0 s = 30.4082 m/s

Therefore, the average velocity for the total trip is 30.4082 m/s.