Sunday

February 1, 2015

February 1, 2015

Posted by **lisa** on Saturday, March 2, 2013 at 9:41pm.

- calculus -
**Reiny**, Sunday, March 3, 2013 at 12:01amIf the original rectangle is x m wide and y m long

then the partitions are x m as well

so we have

2y + 4x = 400

y + 2x = 200

y = 200 - 2x

Area = xy

A = x(200-2x) = 200x - 2x^2

dA/dx = 200 - 4x = 0 for a max of A

200 = 4x

x = 50

then y = 200 - 100 = 100

if x = 50 and y = 100, we get a maximum area

which is xy or 50(100) = 5000 m^2

**Answer this Question**

**Related Questions**

Math OPTIMIZATION - A home gardener plans to enclose two rectangular gardens ...

pre-calc - area of a rectangular region: a farmer wishes to create two ...

Math - A gardenervhas 100 meters of fencing to enclose two adjacent rectangular ...

Algebra - Algebra Word Problems: 1. The length of the floor of a one-storey ...

Algebra 2 - A farmer wants to enclose three sides of a rectangular area that ...

math - a farmer with 10,000 meters of fencing wants to enclose a rectangular ...

Calculus 1 - If you have 280 meters of fencing and want to enclose a rectangular...

Algebra - You have 50 yards of fencing to enclose a rectangular region. Find the...

Math - A farmer uses 1034 meters of fencing to enclose a rectangular region and ...

Math, Quadratic Functions - Eighty metres of fencing are available to enclose a ...