Posted by lisa on Saturday, March 2, 2013 at 9:41pm.
If the original rectangle is x m wide and y m long
then the partitions are x m as well
so we have
2y + 4x = 400
y + 2x = 200
y = 200 - 2x
Area = xy
A = x(200-2x) = 200x - 2x^2
dA/dx = 200 - 4x = 0 for a max of A
200 = 4x
x = 50
then y = 200 - 100 = 100
if x = 50 and y = 100, we get a maximum area
which is xy or 50(100) = 5000 m^2
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