what is the volume of water displaced for 1.1 of pure gold.
1.1 what? grams? troy ounces? newtons?
To find the volume of water displaced by 1.1 grams of pure gold, you need to use the concept of density. Density is defined as the mass of an object divided by its volume. Since we know the mass of the gold (1.1 grams), we need to determine the density of gold to find the volume.
The density of gold is approximately 19.3 grams per cubic centimeter (g/cm³). This means that 1 cubic centimeter of gold weighs 19.3 grams.
To find the volume of gold that displaces 1.1 grams of water, divide the mass of the gold by the density of gold:
Volume of gold = Mass of gold / Density of gold
= 1.1 grams / 19.3 g/cm³
Calculating this will give you the volume of gold in cubic centimeters (cm³).