Posted by Morgan Parker on .
A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile\'s engine cooling system. If your car\'s cooling system holds 4.20 gallons, what is the boiling point of the solution? Make the following assumptions in your calculation; at normal filling conditions, the densities of engine coolant and water are 1.11 g/mL and 0.998 g/mL respectively. Assume that the engine coolant is pure ethylene glycol (HOCH2CH2OH), which is nonionizing and nonvolatile, and that the pressure remains constant at 1.00 atm. Also, you\'ll need to look up the boilingpoint elevation constant for water.

chemistry 
Anonymous,
The first step is to convert the volume of the solution in the radiator to liters.
6.4gal x 3.785L = 24.2266L
Determine the mass of the water in the solution using the 50/50 blend (by volume), and the density of water.
24.2266/2=12.1133L
Water: .998g/molx1000L=998g/L
998g/Lx12.1133L=12089.0734g~12.0Kg
glycol =^ molae mass= 62.0674mol/g
1.11g/ml=1110g/L x 12.1133L = 13445.763g/62.06 = 216.63 mol.
solve for m= mole/Kg
Fnal part.
T=(Kb)(m)
=.512x17.9
=9.1648 + 100 degrees
T= 109.17
=.512