# chemistry

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A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile\'s engine cooling system. If your car\'s cooling system holds 4.20 gallons, what is the boiling point of the solution? Make the following assumptions in your calculation; at normal filling conditions, the densities of engine coolant and water are 1.11 g/mL and 0.998 g/mL respectively. Assume that the engine coolant is pure ethylene glycol (HOCH2CH2OH), which is non-ionizing and non-volatile, and that the pressure remains constant at 1.00 atm. Also, you\'ll need to look up the boiling-point elevation constant for water.

• chemistry -

The first step is to convert the volume of the solution in the radiator to liters.
6.4gal x 3.785L = 24.2266L

Determine the mass of the water in the solution using the 50/50 blend (by volume), and the density of water.
24.2266/2=12.1133L
Water: .998g/molx1000L=998g/L
998g/Lx12.1133L=12089.0734g~12.0Kg

glycol =^ molae mass= 62.0674mol/g
1.11g/ml=1110g/L x 12.1133L = 13445.763g/62.06 = 216.63 mol.

solve for m= mole/Kg
Fnal part.
T=(Kb)(m)
=.512x17.9
=9.1648 + 100 degrees
T= 109.17
=.512

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