Posted by **Cassie** on Friday, March 1, 2013 at 11:17pm.

Given the rate equation...

RATE = ([ Na2S2O3]/time) = k [I-]a [BrO3-]b [HCl]c

1A) You mix together in the proper manner the following:

10.0 mL of .0100 M Potassium Iodide

10.0 mL of .00100 M Sodium thiosulfate

10.0 mL of water

10.0 mL of .0400 M Potassium Bromate

10.0 mL of .100 M HCl

The time to turn blue is... 61 sec

1B) You also mix together in the proper manner the following:

10.0 mL of .0100 M Potassium Iodide

10.0 mL of .00100 M Sodium thiosulfate

20.0 mL of .0400 M Potassium Bromate

10.0 mL of .100 M HCl

The time to turn blue is... 14 sec

Calculate:

The Experimental value of exponent b..._______________ (a)

2) If the exponents a, b, and c have the values:

a = 2; b = 2; c = 0

CALCULATE:

Rate constant k for data in 1B...______________ (b)

3) You mix together in the proper manner the following VOLUMES:

0.0100 M Potassium iodide...9.2 mL

0.0010 M Sodium thiosulfate...6.5 mL

Distilled water...16.8 mL

0.0400 M Potassium Bromate...13.9 mL

0.100 M Hydrochloric acid...6.1 mL

Using the rate constant and rate equation from problem 2),

CALCULATE the time to turn blue...__________________ sec (c)

All i need is explanation on how to do and where to plug in the equation because i am so lost.

thank you!

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