Posted by Cassie on Friday, March 1, 2013 at 11:17pm.
Given the rate equation...
RATE = ([ Na2S2O3]/time) = k [I-]a [BrO3-]b [HCl]c
1A) You mix together in the proper manner the following:
10.0 mL of .0100 M Potassium Iodide
10.0 mL of .00100 M Sodium thiosulfate
10.0 mL of water
10.0 mL of .0400 M Potassium Bromate
10.0 mL of .100 M HCl
The time to turn blue is... 61 sec
1B) You also mix together in the proper manner the following:
10.0 mL of .0100 M Potassium Iodide
10.0 mL of .00100 M Sodium thiosulfate
20.0 mL of .0400 M Potassium Bromate
10.0 mL of .100 M HCl
The time to turn blue is... 14 sec
Calculate:
The Experimental value of exponent b..._______________ (a)
2) If the exponents a, b, and c have the values:
a = 2; b = 2; c = 0
CALCULATE:
Rate constant k for data in 1B...______________ (b)
3) You mix together in the proper manner the following VOLUMES:
0.0100 M Potassium iodide...9.2 mL
0.0010 M Sodium thiosulfate...6.5 mL
Distilled water...16.8 mL
0.0400 M Potassium Bromate...13.9 mL
0.100 M Hydrochloric acid...6.1 mL
Using the rate constant and rate equation from problem 2),
CALCULATE the time to turn blue...__________________ sec (c)
All i need is explanation on how to do and where to plug in the equation because i am so lost.
thank you!
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