Posted by **Anonymous** on Friday, March 1, 2013 at 11:12pm.

Problem 4: Module 8 (30 points)

The Exeter Company produces two basic types of dog toys. Two resources are crucial to the output of the toys: assembling hours and packaging hours. Further, only a limited quantity of type 1 toy can be sold. The linear programming model given below was formulated to represent next week’s situation.

Let, X1 = Amount of type A dog toy to be produced next week

X2 = Amount of type B dog toy to be produced next week

Maximize total contribution Z = 35 X1 + 40 X2

Subject to

Assembling hours: 4 X1 + 6 X2 48

Packaging hours: 2 X1 + 2 X2 18

Sales Potential: X1 < 6

Non-negativity: X1 0, X2 0

Use Excel Solver OR graphical method to find the optimal solution of the problem. If you use Excel Solver, please paste your output here.

Note 1: Place X1 along the horizontal axis and X2 along the vertical axi.

Note 2: Clearly mark the feasible region on the graph.

Note 3: Find the points of intersection points algebraically.

Note 4: Clearly show all steps to find the optimal solution by the graphical method.

## Answer This Question

## Related Questions

- Math! Problem solving.find the whole group using u - Lisa's dog has 4 squeaky ...
- Fractions - lisa's dog has 4 squeaky toys. two thirds of the dog's toys are ...
- math - A company makes two products , namely X and Y. Each product must be ...
- Data Management Probability - A toy manufacturing company that 5% of there toys ...
- 6th grade math - Ye Olde Toy Shoppe wants a set of toys: 1/4 of the toys should ...
- Writing Skills Part 4 - 2.which of the following would most likely be an entry ...
- Mathematics (probability) - A bag contains 3 red and 5 white toys. Rose picked ...
- Maths proportions - 1) Nine milk bottles contain 4.5 litres of milk between them...
- math - two men worked 8 hours each and they built 32 frames for sheds. what is ...
- 9th grade - two men worked 8 hours each and they built 32 frames for sheds. what...

More Related Questions