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March 28, 2017

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Find the slope and the equation of the tangent line to the graph of the function f at the specified point.

f(x)=-10/3x^2+6x+6; (-1, -10/3)

slope ??

tangent line y = ?

  • Math Please Help!! - ,

    f'=+10(6x+6)/(3x^2+6x+6)^2
    slope at x=-1
    f'=0

    y=mx+b=0+b
    -10/3=b
    y=-10/3 is the tangent line.

  • Math Please Help!! - ,

    that wasn't right

  • Math Please Help!! - ,

    is f(x)=-10/(3x^2+6x+6) or is
    f(x)=-(10/3x^2 )+ 6x + 6 ?

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