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December 21, 2014

December 21, 2014

Posted by **Kimberly** on Friday, March 1, 2013 at 9:07pm.

f(x)=-10/3x^2+6x+6; (-1, -10/3)

slope ??

tangent line y = ?

- Math Please Help!! -
**bobpursley**, Friday, March 1, 2013 at 9:18pmf'=+10(6x+6)/(3x^2+6x+6)^2

slope at x=-1

f'=0

y=mx+b=0+b

-10/3=b

y=-10/3 is the tangent line.

- Math Please Help!! -
**Kimberly**, Friday, March 1, 2013 at 9:35pmthat wasnt right

- Math Please Help!! -
**bobpursley**, Friday, March 1, 2013 at 10:32pmis f(x)=-10/(3x^2+6x+6) or is

f(x)=-(10/3x^2 )+ 6x + 6 ?

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