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Math Please Help!!

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Find the slope and the equation of the tangent line to the graph of the function f at the specified point.

f(x)=-10/3x^2+6x+6; (-1, -10/3)

slope ??

tangent line y = ?

  • Math Please Help!! - ,

    slope at x=-1

    y=-10/3 is the tangent line.

  • Math Please Help!! - ,

    that wasn't right

  • Math Please Help!! - ,

    is f(x)=-10/(3x^2+6x+6) or is
    f(x)=-(10/3x^2 )+ 6x + 6 ?

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