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March 6, 2015

March 6, 2015

Posted by **tim2222** on Friday, March 1, 2013 at 8:16pm.

- calculus -
**Reiny**, Friday, March 1, 2013 at 9:41pmy' = 3x^2 - 2x - 8

y '' = 6x - 2

at the point of inflection y'' = 0

6x-2 = 0

x = 2/6 = 1/3

if x=1/3

y = 1/27 - 1/9 - 8/3 + 12

= 250/27

the point of inflection is (1/3 , 250/27)

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