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October 23, 2014

October 23, 2014

Posted by **Kimberly** on Friday, March 1, 2013 at 8:13pm.

f(x)=-10/3x^2+6x+6; (-1, -10/3)

slope ??

tangent line y = ?

- math -
**Knights**, Friday, March 1, 2013 at 9:30pmalready answered by bobpursley

- math -
**Kimberly**, Friday, March 1, 2013 at 9:36pmhe was wrong

- math -
**Reiny**, Friday, March 1, 2013 at 9:55pmKimberly, as I pointed out to you in another post, it is very important to use brackets in this format to establish the correct order of operation, since we cannot "build" fractions here.

bobpursley interpreted your equation as

f(x) = 10/(3x^2 + 6 x + 6)

and his answer is correct according to that equation

the way you typed it ....

f'(x) = (-20/3)x + 6

f'(-1) = 20/3 + 6 =38/3

so the slope is 38/3

equation:

y + 10/3 = (38/3)(x+1)

times 3

3y + 10 = 38(x+1)

3y = 38x + 38 - 10

3y = 38x + 28

y = (38/3)x + 28/3

or

38x - 3y = -28

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