posted by Jane Brown on .
Assume the body temperature of healthy adults are normally distributed with a mean of 98.20 degrees F (based on data from the Uniservity of Maryland researchers).a. If you have a body temperature of 99.oo degrees F, what is your percentile score? b. Convert 99.00 degrees F to a standard score (or a z-score), c. Is a body temperature of 99.00 degrees F unusual? why or why not? d.Fifty adults are randomly selected. What is the liklihood that the meand of their body temperatures is 97.98 degrees F or lower? e. A person's body temperature is found to be 101.00 degrees f. Is the result unusual? why or why not? f. What body temoerature is the 95th percentile? g. What body temperature is the 5th percentile? h. Bellevue Hospital in New York uses 100.6 degrees F as the lowest temperature considered to indicate a fever. What percentage of normal and healthy adults would be considered to have a fever? Does this percentage suggest that a cutoff of 100.6 degrees F is appropriate?
What is the standard deviation?
a, b. Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
c. Same as above.
d. Z = (score-mean)/SEm
SEm = SD/√n
Use same table.
e. Same process as a.
f, g. Start with the table and insert the Z score in the top equation.
h. Same process as a.