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March 27, 2015

March 27, 2015

Posted by **Brandi** on Friday, March 1, 2013 at 8:27am.

- chemistry -
**Devron**, Friday, March 1, 2013 at 9:23amThe heat change for both objects will be equal, so you need two equations and they need to be set to each other. The equation to use is the following:

q=mcT∆

Conditions for 1

m1=mass1=115g

c1=specific heat1=?

T∆1=25.0°C-27.0ºC=-2.0Cº

Conditions for 2:

m2=mass2=100.0g

c2=specific heat2=4.18 (J/g°C)

T∆2=25.0°C-60.ºC=-30.0ºC

m1c1∆T1=m2c2∆T2

(115g)c1(-2.0Cº)=(100.0g)(4.18 (J/g°C))(-30.0ºC)

Solve for c1,

c1=[(100.0g)(4.18 (J/g°C))(-30.0ºC)]/[(115g)(-2.0Cº)]

c1=(-1.25 x 10^4 J/)(-2.3 x 10^2 gºC)

c1=54.3 J/g°C

****I think; I havent had to do this type of calculations in years.

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