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January 31, 2015

January 31, 2015

Posted by **Michelle** on Friday, March 1, 2013 at 2:44am.

- Chemistry -
**Devron**, Friday, March 1, 2013 at 3:14am(100)*1/2^n=1

Solve for n

1/2^n=1/100

2^n=100

n=ln(100)/ln(2)

n* the number of days (11.4) =should give you the length of time it takes for Radium-223 to decrease to 1.00% of its initial value.

- Chemistry -
**Michelle**, Friday, March 1, 2013 at 3:40am75.7 days

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