Posted by **ruru mq** on Friday, March 1, 2013 at 2:14am.

Help me solve this physics homework:

in sense we all have kinetic energy,even when we are standing still.the earth with a radius of 6.37*10power6 m,rotates about its axis once a day.ignoring the earths rotation about the sun,what is the K.E of a 50Kg man standing on the surface of the earth.

- physics -
**drwls**, Friday, March 1, 2013 at 7:19am
It will depend upon the longitude where he is standing. The velocity of a person at the equator, in an Earth-fixed coordinate system, is

V = 2*pi*6.37*10^6 m/(24*3600 sec)

= 463 m/s

Use that velocity with the formula for kinetic energy, (1/2)MV^2

## Answer This Question

## Related Questions

- physics - please help - Assume the earth is a uniform sphere and that its path ...
- Physics - Assume that the earth is a uniform sphere and that its path around the...
- physics - Assume that the earth is a uniform sphere and that its path around the...
- Physics - Calculate the kinetic energy that the earth has because of (a) its ...
- PHYSICS - Calculate the kinetic energy that the earth has because of (a) its ...
- Physics - Calculate the kinetic energy that the earth has because of (a) its ...
- Physics - Calculate the kinetic energy that the earth has because of (a) its ...
- Physics - Calculate the kinetic energy that the earth has because of (a) its ...
- physics - Calculate the kinetic energy that the earth has because of its ...
- Physics - Calculate the kinetic energy that the earth has because of its ...

More Related Questions