posted by Mike on .
What is the complete and net ionic equations for: Cu+Zn+2HCl--> ZnCl2+Cu+h2
I would omit Cu from both sides since it doesn't react.
Zn(s) + 2H^+(aq) + 2Cl^-(aq) ==>Zn^2+(aq) + 2Cl^-(aq) + H2(g) is the complete ionic equation.
Cancel those substances that appear on both sides and that leaves the net ionic equation.