trig
posted by Julise Alliance on .
If sin theta is equal to 5/13 and theta is an angle in quadrant II find the value of cos theta, sec theta, tan theta, csc theta, cot theta.

make a sketch of your triangle
since sinØ = opposite /hypotenuse = 5/13
opposite = 5 and hypotenuse = 13
by Pythagoras:
x^2 + 5^2 = 13^2
x^2 +25 = 169
x^2 = 144
x = ± 12 , but in quadrant II, x =  12
sinØ = 5/13 , cscØ = 13/5
cosØ = 12/13 , secØ =  13/12
tanØ = 5/12 = 5/12 , cot Ø = 12/5 
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