Posted by **Julise Alliance** on Thursday, February 28, 2013 at 10:44pm.

If sin theta is equal to 5/13 and theta is an angle in quadrant II find the value of cos theta, sec theta, tan theta, csc theta, cot theta.

- trig -
**Reiny**, Thursday, February 28, 2013 at 11:10pm
make a sketch of your triangle

since sinØ = opposite /hypotenuse = 5/13

opposite = 5 and hypotenuse = 13

by Pythagoras:

x^2 + 5^2 = 13^2

x^2 +25 = 169

x^2 = 144

x = ± 12 , but in quadrant II, x = - 12

sinØ = 5/13 , cscØ = 13/5

cosØ = -12/13 , secØ = - 13/12

tanØ = 5/-12 = -5/12 , cot Ø = -12/5

- trig -
**Anonymous**, Sunday, June 8, 2014 at 10:15pm
poop

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