mass of the metal 7.26g

volume of water in the calorimeter 10mL
initial temp of water in calorimeter 21.5 degrees C
initial temp of metal 95.5 d C
final temp in mixture in calorimeter 23.8 D C
question:
calculate the energy lost by the metal taking into consideration that it is equal to the energy absorbed by the water plus the correction factor for the calorimeter

please help

To calculate the energy lost by the metal, we need to consider the energy absorbed by the water and the correction factor for the calorimeter. We can use the principle of energy conservation, which states that energy lost by one object is equal to the energy gained by another object.

First, let's calculate the energy absorbed by the water. This can be determined using the formula:

Energy absorbed by water = mass of water * specific heat capacity of water * change in temperature

The mass of the water can be calculated from its volume using the density of water, which is approximately 1 g/mL.

Mass of water = volume of water * density of water

Next, we need to calculate the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.

Now, let's calculate the change in temperature of the water. It can be found by subtracting the initial temperature from the final temperature.

Change in temperature of water = final temperature - initial temperature of water

Now, let's calculate the energy absorbed by the water:

Energy absorbed by water = mass of water * specific heat capacity of water * change in temperature of water

Next, we need to calculate the correction factor for the calorimeter. This correction factor takes into account any heat loss or gain by the calorimeter. We assume it to be negligible in this case.

Finally, we can find the energy lost by the metal by using the principle of energy conservation:

Energy lost by the metal = Energy absorbed by water + correction factor for calorimeter

Substitute the values into these equations and perform the calculations to find the energy lost by the metal.

To calculate the energy lost by the metal, we need to first calculate the energy absorbed by the water and the correction factor for the calorimeter.

Step 1: Calculate the energy absorbed by the water.
The energy absorbed by the water can be calculated using the formula:

Energy absorbed by water = mass of water x specific heat capacity of water x change in temperature

Given:
- Volume of water = 10 mL = 10 cm³
- The density of water is approximately 1 g/cm³ (at room temperature and pressure)
- Specific heat capacity of water = 4.18 J/g°C (approximately)

First, let's calculate the mass of water:
mass of water = volume of water x density of water
mass of water = 10 cm³ x 1 g/cm³
mass of water = 10 g

Next, calculate the change in temperature:
change in temperature = final temperature - initial temperature
change in temperature = 23.8°C - 21.5°C
change in temperature = 2.3°C

Now, calculate the energy absorbed by the water:
Energy absorbed by water = mass of water x specific heat capacity of water x change in temperature
Energy absorbed by water = 10 g x 4.18 J/g°C x 2.3°C

Step 2: Calculate the correction factor for the calorimeter.
The correction factor for the calorimeter accounts for any heat absorbed or lost by the calorimeter itself during the experiment. This value is typically provided in the experiment or can be obtained from the calorimeter's specifications.

Let's assume the correction factor for the calorimeter is 5 J.

Step 3: Calculate the energy lost by the metal.
The energy lost by the metal is equal to the energy absorbed by the water plus the correction factor for the calorimeter.

Energy lost by the metal = Energy absorbed by water + Correction factor for the calorimeter
Energy lost by the metal = (10 g x 4.18 J/g°C x 2.3°C) + 5 J

You can now calculate the energy lost by the metal by substituting the values into the equation.