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3 MgCl2(aq) + 2 Na3PO4(aq) ==> Mg3(PO4)2(s) + 6 NaCl(aq)
How many milliliters of 0.0800 M Na3PO4(aq) will react with 0.060 mol of MgCl2(aq)?

  • chemistry - ,

    0.060 mol MgCl2 x (2 mols Na3PO4/3 mol MgCl2) = 0.060 x (2/3) = mols Na3PO4.
    Then M = mols/L. You know mols and M, solve for L and convert to mL.

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