And please can you show me all your work.
make a sketch.
let the distance of the foot from the wall be x ft
label the base x
the length of the ladder (the hypotenuse) is
one foot more than twice the distance from the wall
---- 2x + 1
mark the hypotenuse 2x + 1
and of course the height is 15
so in your right-angled triangle
15^2 + x^2= (2x+1)^2
225 + x^2 = 4x^2 + 4x + 1
0 = 3x^2 + 4x - 224
Using the quadratic formula:
x = (-4 ± √2704)/6
= (-4 ± 52)/6
= 8 or a negative, which we would reject
So the ladder is 8 ft from the wall
height = 15
base = 8
ladder = 17
is 15^2 + 8^2 = 17^2 ?? , YES!
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