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February 27, 2015

February 27, 2015

Posted by **Jack** on Thursday, February 28, 2013 at 7:11pm.

- Algebra 1 -
**Jack**, Thursday, February 28, 2013 at 7:12pmAnd please can you show me all your work.

- Algebra 1 -
**Reiny**, Thursday, February 28, 2013 at 9:52pmmake a sketch.

let the distance of the foot from the wall be x ft

label the base x

the length of the ladder (the hypotenuse) is

one foot more than twice the distance from the wall

---- 2x + 1

mark the hypotenuse 2x + 1

and of course the height is 15

so in your right-angled triangle

15^2 + x^2= (2x+1)^2

225 + x^2 = 4x^2 + 4x + 1

0 = 3x^2 + 4x - 224

Using the quadratic formula:

x = (-4 ± √2704)/6

= (-4 ± 52)/6

= 8 or a negative, which we would reject

So the ladder is 8 ft from the wall

check:

height = 15

base = 8

ladder = 17

is 15^2 + 8^2 = 17^2 ?? , YES!

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