Posted by **Jack** on Thursday, February 28, 2013 at 7:11pm.

A ladder is resting against a wall. The top of the ladder touches the wall at a height of 15 feet and the length of the ladder is one foot more than twice the distance from the wall. Find the distance from the wall to the bottom of the ladder. (Hint: Use the Pythagorean Theorem.)

- Algebra 1 -
**Jack**, Thursday, February 28, 2013 at 7:12pm
And please can you show me all your work.

- Algebra 1 -
**Reiny**, Thursday, February 28, 2013 at 9:52pm
make a sketch.

let the distance of the foot from the wall be x ft

label the base x

the length of the ladder (the hypotenuse) is

one foot more than twice the distance from the wall

---- 2x + 1

mark the hypotenuse 2x + 1

and of course the height is 15

so in your right-angled triangle

15^2 + x^2= (2x+1)^2

225 + x^2 = 4x^2 + 4x + 1

0 = 3x^2 + 4x - 224

Using the quadratic formula:

x = (-4 ± √2704)/6

= (-4 ± 52)/6

= 8 or a negative, which we would reject

So the ladder is 8 ft from the wall

check:

height = 15

base = 8

ladder = 17

is 15^2 + 8^2 = 17^2 ?? , YES!

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