Wednesday

April 23, 2014

April 23, 2014

Posted by **Kevin** on Thursday, February 28, 2013 at 6:56pm.

1)y=ln(2x^6-15)

2)y= 3√ 2x^2-3x-1/5

3) y= x^4/x^2+1

- Math -
**Reiny**, Thursday, February 28, 2013 at 9:44pm1. dy/dx = 12x^5 /(2x^6 - 15) ---- routine

2. dy/dx = 6√2 x - 3 ---- routine

3. the way you typed it,

y = x^4/x^2 + 1

y = x^2 + 1

dy/dx = 2x

if you meant x^4/(x^2+ 1) , then you would use the quotient rule. See how critical it is to use brackets ?

- Math -
**Kevin**, Thursday, February 28, 2013 at 10:16pmthere is no brackets for question 3. Although i am still confused. would you be able to give step by step solutions?

**Related Questions**

Calc - a) y =ln(x-1) find dy/dx=? b) y=3 ln x - ln (1/x) where x >0, dy/dx...

Math differentiation - Can somebody please check these over for me? I really ...

A big one! - Using logarithmic differentiate technique, find dy/dx y = [(x-3)³(x...

Property of logarithms - Using property of logarithms, how do I prove derivative...

Calculus - derivatives - Okay, I want to find the derivative of (x^x)^(x^x)... ...

Calc - y=ln(x+1) +ln(x-1) find dy/dx I have trouble with this problem since i'm ...

integration by parts - s- integral s ln (2x+1)dx ? = ln(2x+1)x - s x d( ln (2x+1...

Math - Find the dy/dx for each equation a) y=ln(2x^6-15) b) y= 3√2x^2-3x-1...

calculus - find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx ...

Calculus - Orthogonal Trajectories - Find the orthogonal trajectories of the ...