Posted by Kevin on Thursday, February 28, 2013 at 6:56pm.
Find the dy/dx for each of the following
1)y=ln(2x^615)
2)y= 3√ 2x^23x1/5
3) y= x^4/x^2+1

Math  Reiny, Thursday, February 28, 2013 at 9:44pm
1. dy/dx = 12x^5 /(2x^6  15)  routine
2. dy/dx = 6√2 x  3  routine
3. the way you typed it,
y = x^4/x^2 + 1
y = x^2 + 1
dy/dx = 2x
if you meant x^4/(x^2+ 1) , then you would use the quotient rule. See how critical it is to use brackets ?

Math  Kevin, Thursday, February 28, 2013 at 10:16pm
there is no brackets for question 3. Although i am still confused. would you be able to give step by step solutions?
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