Posted by **Kevin** on Thursday, February 28, 2013 at 6:56pm.

Find the dy/dx for each of the following

1)y=ln(2x^6-15)

2)y= 3√ 2x^2-3x-1/5

3) y= x^4/x^2+1

- Math -
**Reiny**, Thursday, February 28, 2013 at 9:44pm
1. dy/dx = 12x^5 /(2x^6 - 15) ---- routine

2. dy/dx = 6√2 x - 3 ---- routine

3. the way you typed it,

y = x^4/x^2 + 1

y = x^2 + 1

dy/dx = 2x

if you meant x^4/(x^2+ 1) , then you would use the quotient rule. See how critical it is to use brackets ?

- Math -
**Kevin**, Thursday, February 28, 2013 at 10:16pm
there is no brackets for question 3. Although i am still confused. would you be able to give step by step solutions?

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