Posted by C on Thursday, February 28, 2013 at 5:34pm.
If centre has (6,8) and one end of the diameter has (4,2), add Δx and Δy to the centre to get the other end of the diameter, namely,
(Δx,Δy) = (6-4, 8-2) = (2,6)
So the other end of the diameter would be (6+2,8+6)=(8,14).
Check: the mid-point of the diameter should be the centre:
((4+8)/2,(2+14)/2)=(6,8) = centre of circle.
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