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March 28, 2017

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Find dy/dx by implicit differentiation.

x cos y + y cos x = 1

  • calculus - ,

    just use the product rule and go for it:

    cosy - x siny y' + y' cosx - y sinx = 0
    y'(cosx - x siny) = y sinx - cosy

    y' = (y sinx - cosy) / (cosx - x siny)

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