Tuesday

July 29, 2014

July 29, 2014

Posted by **Molly** on Thursday, February 28, 2013 at 2:29pm.

y'=

- calculus -
**Steve**, Thursday, February 28, 2013 at 3:32pmjust use the product and chain rules:

y' = -7e^-7x cos5x - 5e^-7x sin5x

= -e^-7x (7cos5x + 5sin5x)

**Related Questions**

calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...

Math - Calculus - The identity below is significant because it relates 3 ...

Calculus - which of the following integrals results from making the substitution...

Calculus - what is the limit n to infinite of cos1*cos(1/2)*cos(1/4)*cos(1/8)*...

Calculus - Evaluate (Integral) sin 4x cos^2 4x dx. A. Cos^3(4x)/3 + C B. -Cos^3(...

Calculus - Evaluate the integral sin4x cos^2 4x dx A. cos^3 4x/3 +C B. - cos^3 ...

Calculus (help Steve plz) - 1) if w = <-8, 15>, find ||w||? 2) which ...

calculus - pleaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaasw help can you pleaaaaase ...

Calculus - Let OP be any vector with direction angles theta, beta, and gama. ...

Math - verify the following identity used in calculus: cos(x+h)-cos(x)/h=cos(x)[...