Posted by Trevor on Thursday, February 28, 2013 at 12:00pm.
at water depth y, the radius of the surface is 2y/5, so y = 5r/2
v = 1/3 pi r^2 h = 1/3 pi (25y^2/4)(y) = 25pi/12 y^3
dv/dt = 25pi/12 * 3y^2 dy/dt = 25pi/4 y^2 dy/dt
3 = 25pi/4 * 25 dy/dt
dy/dt = 12 / 625pi
Seems kinda slow - better double check my algebra
Ahh. I see - I did the wrong substitution
r = 2y/5
Make that change and follow it through
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