physics
posted by allan jordan on .
A dray horse is being pulled by a rope across a level plow field by a force of 750.0N exerted at an angle of 47° above the horizontal. If the horse’s velocity is constant and the coefficient of friction is ì=.21, determine the mass of the horse.

Wt. = m*g = m*9.8 = Wt. in Newtons.
Fp = 9.8m*sin(0) = 0 = Force parallel to the field.
Fv=9.8m*cos(0)  750*sin47 = 9.8m548.5=
Force perpendicular to the field.
Fk = u*Fv=0.21(9.8m548.5)=2.06m115.19 = Force of kinetic energy.
750*cos47FpFk = m*a
511.50(2.06m115.19) = m*0
511.5  2.06m+115.19 = 0
2.06m = 626.7
m = 304 kg.