Posted by suzanne on Thursday, February 28, 2013 at 1:45am.
a soccer player kicks a rock horizontally off a 40.0mhigh cliff into a pool of water. if the player hears the sound of the splash 3.00 s later, what was the initial speed given to the rock? assume the speed of sound in air to be 343m/s.

physics  drwls, Thursday, February 28, 2013 at 2:32am
Neglecting air friction, the time it will take the rock to hit the water is
sqrt(2H/g) = 2.857 seconds. That means the sound of the splash takes 3  2.857 = 0.143 seconds to be heard, after hitting water. Sound travelled 49.05 m in that time. Since the cliff is 40 m high, the horizontal distance travelled by the rock was (from the Pythagorean theorem)
sqrt[(49.05)^2 (40)^2] = 28.4 m
The rock's initial speed (and constant horizontal speed) was 28.4 m/2.857 s = 9.84 m/s

physics  warnu, Wednesday, December 24, 2014 at 11:17pm
9.84 m/s
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