Posted by **AwesomeGuy** on Thursday, February 28, 2013 at 1:05am.

Solve the equation for all values of x.

2sin(2x)-√3=0, on the interval [0,2π).

- Trigonometry -
**Steve**, Thursday, February 28, 2013 at 10:18am
sin2x = √3/2

so, 2x = π/3, 2π/3, 7π/3, 8π/3

x = π/6, π/3, 7π/6, 4π/3

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