Posted by **Anonymous...urgent!** on Thursday, February 28, 2013 at 12:54am.

ABC is an acute angle triangle with points D and E on BC and AC, respectively such that BE and AD are altitudes. AD and BE intersect at H. If ∠BCA=39∘ and ∠EBA=2∠DAB, what is the measure of ∠ABC (in degrees)?

- geometry! -
**Steve**, Thursday, February 28, 2013 at 10:28am
We have a bunch of right triangles here

BCA=39, so CAD = 51

BEA=90, so EHA = 39

vertical angle DHB is thus 39

HDB = 90, so HBD = 51

Now we know all the angles

A = 51+x

B = 51+2x

so, 39+51+x+51+2x = 180

x = 13

ABC = 26

- geometry! -
**Aditya madhukar**, Wednesday, March 27, 2013 at 11:30am
85

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