posted by Anonymous...urgent! on .
ABCD is a parallelogram. E is a point on AB such that 234×AE=EB. Let DE intersect AC at F. What is the ratio AC:AF?
oin AC and DE. Triangles AFE and DFC are similar.
so AF/FC = AE/CD = AE/EB also AE + EB = AB ie AE +234AE =AB so AE/AB =1/235
so AF/FC = 1/235 FC = 235 AF now, AC = AF +FC = 236AF ie AC/AF = 236/1
ie AC : AF = 236 : 1