The length of a rectangle is 10 in less than twice its width. if the area is 2160 what are the dimensions?
algebra - PsyDAG, Thursday, February 28, 2013 at 11:21am
L = 2W -10
L * W = 2160
Substitute 2W-10 for L in second equation and solve for W. Insert that value into the first equation and solve for L. Check by inserting both values into the second equation.