Physics
posted by Rachel on .
You push a block of mass m against a horizontal spring, compressing the spring a distance x. Then you release the block, and the spring sends it sliding across a tabletop. It stops a distance d from where you release it. Let k be the spring constant. What is the coefficient of kinetic friction between the block and the table? (Use any variable or symbol stated above along with the following as necessary: g for the acceleration of gravity.)
μk =

Use conservation of energy E = K + U
Ui (initial potential from spring) = Kf (final kinetic energy
1/2 kx^2 = 1/2 mv^2
v = x*sqrt(k/m)
From kinematics:
d = (Vf^2Vi^2) / (2a)
d = (x*sqrt(k/m))^2 / (2a) (substituting our v from above)
d = (kx^2) / (2*ma)
We know from forces that friction = µ*N and N = mg
the net force on the object after leaving the spring will be that from friction, therefore F = µmg = ma
µmg = (kx^2) / (2d)
µ = (kx^2) / (2dmg)